Description
Given the head
of a singly linked list, reverse the list, and return the reversed list.
Example 1:
Input: head = [1,2,3,4,5]
Output: [5,4,3,2,1]
Constraints:
- The number of nodes in the list is the range
[0, 5000]
. -5000 <= Node.val <= 5000
Solution
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struct ListNode* reverseList(struct ListNode* head){
struct ListNode *next = NULL;
while (head) {
struct ListNode *tmp = head->next;
head->next = next;
next = head;
head = tmp;
}
return next;
}
Runtime: 0 ms, faster than 100.00% of C online submissions for Reverse Linked List.
Memory Usage: 6.5 MB, less than 13.93% of C online submissions for Reverse Linked List.