Leetcode #2 Add Two Numbers

Posted by blueskyson on February 12, 2021

Description

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example 1:

Input: l1 = [2,4,3], l2 = [5,6,4]
Output: [7,0,8]
Explanation: 342 + 465 = 807.

Example 2:

Input: l1 = [0], l2 = [0]
Output: [0]

Example 3:

Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
Output: [8,9,9,9,0,0,0,1]

Constraints:

  • The number of nodes in each linked list is in the range [1, 100].
  • 0 <= Node.val <= 9
  • It is guaranteed that the list represents a number that does not have leading zeros.

Solution

c++

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/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
        int carry = 0;
        ListNode *ret = nullptr;
        ListNode **indirect = &ret;
        while (l1 || l2 || carry) {
            int n1 = 0, n2 = 0, n3;
            if (l1 != nullptr) {
                n1 = l1->val;
                l1 = l1->next;
            }
            
            if (l2 != nullptr) {
                n2 = l2->val;
                l2 = l2->next;
            }
            
            n3 = n1 + n2 + carry;
            if (n3 > 9) {
                n3 -= 10;
                carry = 1;
            } else {
                carry = 0;
            }
            
            *indirect = new ListNode(n3);
            indirect = &((*indirect)->next);
        }
        return ret;
    }
};

Runtime: 20 ms, faster than 95.89% of C++ online submissions for Add Two Numbers.

Memory Usage: 71.1 MB, less than 69.37% of C++ online submissions for Add Two Numbers.

go

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/**
 * Definition for singly-linked list.
 * type ListNode struct {
 *     Val int
 *     Next *ListNode
 * }
 */
func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode {
    carry := 0
    var ret *ListNode = nil
    var indirect **ListNode = &ret
    for (l1 != nil || l2 != nil || carry != 0) {
        n1, n2, sum := 0, 0, 0
        if l1 != nil {
            n1 = l1.Val
            l1 = l1.Next
        }

        if l2 != nil {
            n2 = l2.Val
            l2 = l2.Next
        }

        sum = n1 + n2 + carry
        if sum > 9 {
            sum -= 10
            carry = 1
        } else {
            carry = 0
        }

        *indirect = &ListNode{ Val: sum, Next: nil }
        indirect = &((*indirect).Next)
    }
    return ret
}

Runtime 8 ms Beats 90.51%

Memory 4.7 MB Beats 46.14%